Posted: April 21st, 2017
If we assume that gases in ballons are ideal, the deal gas law can be applied:
p * V = n * R * T,
R being the gas constant, R = 8.314 J/(K * mol).
For the first ballon, these are the information:
p1 = 735 Torr = 97992 Pa
V1 = 2 L = 0.002 m^3
T = 298 K,
end when inserted into equation:
p1 * V1 = n1 * R * T,
n1 = (p1 * V1) / (R * T) = 0.0791 mol.
The same is for the second ballon:
p2 = 1470 Torr = 195984 Pa
V2 = 1 L = 0.001 m^3
p2 * V2 = n2 * R * T,
n2 = (p2 * V2) / (R * T) = 0.0791 mol.
Now we apply the law for the third ballon with these information:
p3 = 2940 Torr = 391968 Pa
n3 = n1 + n2 = 0.158 mol
p3 * V3 = n3 * R * T,
V3 = n3 * R * T / p3 = 0.001 m^3 = 1 L
Place an order in 3 easy steps. Takes less than 5 mins.