Posted: April 21st, 2017

If we assume that gases in ballons are ideal, the deal gas law can be applied:

p * V = n * R * T,

R being the gas constant, R = 8.314 J/(K * mol).

For the first ballon, these are the information:

p1 = 735 Torr = 97992 Pa

V1 = 2 L = 0.002 m^3

T = 298 K,

end when inserted into equation:

p1 * V1 = n1 * R * T,

n1 = (p1 * V1) / (R * T) = 0.0791 mol.

The same is for the second ballon:

p2 = 1470 Torr = 195984 Pa

V2 = 1 L = 0.001 m^3

p2 * V2 = n2 * R * T,

n2 = (p2 * V2) / (R * T) = 0.0791 mol.

Now we apply the law for the third ballon with these information:

p3 = 2940 Torr = 391968 Pa

n3 = n1 + n2 = 0.158 mol

p3 * V3 = n3 * R * T,

V3 = n3 * R * T / p3 = 0.001 m^3 = 1 L

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